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2a)
Log2 (x – 2y) =0——->{1}
Log2 (4y – x) = 1——->{2}
X-2y=2^0——->{1}
-x+4y=2^1——->{2}
X-2y=0
-x+4y=2
2y=2
Y=1
Sub y=1 into eqn{1}
X-2(1)=0
X-2=0
X=2
Therefore X=2 and Y=-1
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