# WAEC 2018 Physics Practical Solution Answer – May/June Expo

## WAEC Physics Practical Solution Questions and Answer – MAY/JUNE 2018 Expo Runz.

3)
Tabulate
s/n 1,2,3,4,5
D(cm) 25,35,50,65,80
I(A) 1.99,1.75,1.55,1.44,1.36
I^(A^-1) 0.530,0.571,0.645,0.694,0.735
Lo(j^) -0.2984,-0.2434,-0.1904,-0.1586,-0.1337
3iii)
3viiii)
slope Dvertical/Dhorizontal
=1.41-1.00/80-25
=0.4/55
S=0.00727
3x)
from the graph C=32cm
3xi)
K=c/2=33/2=16cm
3xii)
-precautions-
take any two
i)I removed key when reading is not taking
ii)I ensured tight connections at the terminals
iii)I avoided parallax error when taking reading from the ammeter.
3bii)
i)length – longer wires have greater resistance.
ii)thickness – smaller diameter wires have greater resistance.
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2ai)
fo=15cm
2av)
a=60.00cm
b=20.00cm
Hence L=a/b=60.00/20.00
L=3
2avi)
TABULATE
S/N:1,2,3,4,5
b(cm):20.00,25.00,35.00,40.00
a(cm):60.00,37.50,30.00,26.25,24.00
L=a/b:3.00,1.50,1.00,0.75,0.60
2avii)
Slope=Change in L/Change in a
=(3-0.25)/(60-18.6)
=2.75/41.4
=0.006642
2aviii)
S^-1=1/S
=(1/0.0066425cm)
S=15.05
S=15cm
2aix)
PRECAUTIONS
-I ensured that all apparatus are in straight line
-I avoided error due to parallax when reading the metre rule
-I avoided zero error on the metre rule
2bi)
u=10cm
f=15cm
Using 1/v+1/u=1/f
1/f-1/u=1/v
1/v=1/15-1/10
1/v=(2-3)/30
1/v=-1/30
v=-30cm
The characteristics of image formed are:
-It is virtual
-It is enlarged and magnified ie twice or two times as big as the object m=2
2bii)
The concave mirror mounted in its holder is moved to and fro in front of the screen until a sharp image of the cross wire of the ray box is formed on the screen adjacent of the object.The distance between the mirror and the screen was measured as 30cm since the radius of curvature r=2fo then half is distance
2bi)
The characteristics of imaged formed are :
i)It is virtual
ii) It is enlarged or magnified i.e. twice or two times bigger as the object(m=2)
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1)
Tabulate
S/n 1,2,3,4,5
L(cm) 90.00,80.00,70.00,60.00,50.00
T(s) 38.30,35.40,33.40,29.60,27.50
T=t/20(s) 1.92,1.77,1.67,1.48,1.38
sqrL(cm^1/2) 9.49,8.94,8.37,7.75,7.07
1vii)
1ix)
slope (s) = D vertical/D horizontal
= 1.90-155/9.49-775
=0.35/1.75
s=0.201
1x)
g=4^2/s^2
=4*(3.142)^2/(0.201)^2
=977.4cm1s^2

1xii)
-precautions-
Take Any Two
i)I avoided conical oscillation
ii)I avoided drought
iii)I avoided parallax error in taking reading from the metre rule
iv)I avoided zero error in taking reading from the stop watch

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